Xyz =0we know thatx3 y3 z3 −3xyz = (xyz)(x2 y2 z2 −xy−yz−zx)then⇒ x3 y3 z3 −3xyz = 0⇒ x3 y3 z3 = 3xyz prove (xy)^3 (yz)^3 (zx)^3=3 (xy) (yz) (zx) Brainlyin nik119 nik119 Math Secondary School answer answered0 votes 1 answer If x y z = 0, prove that (xa yb zc), (yc za xb), (zb xc ya) = xyz(a b c), (c a b), (b c a) asked in Mathematics by AsutoshSahni (526k points) determinant;

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Prove that (x-y)^3 (y-z)^3 (z-x)^3=3(x-y)(y-z)(z-x)
Prove that (x-y)^3 (y-z)^3 (z-x)^3=3(x-y)(y-z)(z-x)-` X ` Y Z =` 33X ` ` ` Z = 5 ` X 2Y Z =` 3 ` Here are the seven steps 1 Pick a letter (If one of the equations has only two letters, choose the ` `letter that is missing) 2 Pick an equation that contains that letter 3 Solve for that letter in that equation 4 Substitute what you get into any other equations that contains that letter, ` `and simplify 5 Now you have only twoAnswer 2 on a question Prove that (xyz)³x³y³z³=3(xy)(yz)(zx) the answers to answersincom




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Evaluate an expression 41 Multiply (zx)3 by (zx) The rule says To multiply exponential expressions which have the same base, add up their exponents In our case, the common base is (zx) and the exponents are 3 and 1 , as (zx) is the same number as (zx)1 The product is therefore, (zx)(31) = (zx)4Click here 👆 to get an answer to your question ️ Prove that (xy)3 (yz)3 (zx)3 3(xy)(yz)(zx) Using properties of determinants, prove that (x,y,z)(x^2,y^2,z^2)(x^3,y^3,z^3) = xyz(xy)(yz)(zx) asked in Mathematics by Aria (60k points) determinant;
We know the corollary if abc = 0 then a3 b3 c3 = 3abcUsing the above identity taking a = x−y, b = y−z and c= z−x, we have abc= x−yy−zz −x= 0 then the equation (x− y)3 (y−z)3 (z−x)3 can be factorised as follows(x−y)3 (y−z)3 (z−x)3 = 3(x−y)(y−z)(z−x)Hence, (x−y)3 (y−z)3 (z −x)3 = 3(x−y)(y −z)(z −x) The question given is Show that $(xyz)^3(yzx)^3(zxy)^3(xyz)^3=24xyz$ What I tried is suppose $a=(yzx),\ b=(zxy)$ and $c=(xyz)$ and then noted that $abc=xyz$ So the quest What I tried is suppose $a=(yzx),\ b=(zxy)$ and $c=(xyz)$ and then noted that $abc=xyz$ Prove that `Detx,x^2,x^3,y,y^2,y^3,z,z^2,z^3=xyz(xy)(yz)(zx)` Let A be a square matrix of order n;
This is the Solution of Question From RD SHARMA book of CLASS 9 CHAPTER POLYNOMIALS This Question is also available in R S AGGARWAL book of CLASS 9 You can FSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreAnswer 1 on a question Prove that (xy)³(yz)³(zx)³3(xy)(yz)(z x)=0 the answers to smartanswersincom




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Prove that (x y)3 (y z)3 (z x)3 = 3(x y) (y z) (z x) Best answer Let (x y) = a, (y z) = b and (z x) = c Then, a b c = (x y) (y zProve that (xy)^3(yz)^3(zx)^33(xy)(yz)(zx)=2(x^3y^3z^33xyz) Prove that (xy)3(yz)3(zx)33(xy)(yz)(zx)=2(x3y3z33xyz) Polynomials class If ` (xy)/(p^(3)q^(3)) = (yz)/(q^(3)r^(3)) = (zx)/(r^(3)p^(3))`, then prove that x y z = 0 P and Q have some coins with them The ratio of the numbers of coins with P




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Example 1 Example 2 Example 3 Example 4 Example 5Ask a Question Verify that (i) x^3 y^3 z^3 – 3xyz = 1/2(x y z)(x y)^2 (y z)^2 (z x)^2 ← Prev Question Next Question → 0 votes 41 Question 33 (OR 1st Question) Using the properties of determinants, prove that (y z)2 x2 x2 y2 (z x)2 y2 z2 z2 (x y)2 2xyz (x y z)3 (y z)2 x2 x2 y2 (z x)2 y2 z2 z2 (x y)2 Applying C2 > C2 C1 = (y z)2 x2 (y z)2 x2 y2 (z x)2 y2 y2 z2




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First, subtract $3xyz$ from both sides of the equation $$x^3y^3z^3=3(xyzxyz) \\ x^3y^3z^33xyz = 3(xyz)$$ Now, using this factorisation, observe $$ (xyz)(x^2y^2z^2xyyzzx)=3(xyz)$$ Since $x,y$, and $z$ are positive integers which implies $xyz\neq 0$, you can divide the equation by $xyz$ to get $$ x^2y^2z^2 xyyzzx = 3$$ Now, from the above equation, it's easy to observe that $$(xSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more👍 Correct answer to the question Prove that (xy)^3(yz)^3(zx)^33(xy)(yz) (zx)=2(x^3y^3z^33xyz) eanswersin



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Using Properties of Determinants, Prove that (2y,Yzx,2y),(2z,2z,Zxy),(Xyz,2x,2x)=(XYZ)^3 CBSE CBSE (Arts) Class 12 Question Papers 17 Textbook Solutions Important Solutions 24 Question Bank Solutions Concept Notes & Videos 532 Time Tables 18 Syllabus Advertisement Remove all ads Using Properties of Determinants, Prove that (2y,YzLHS = `(x y, y z, z x),(z x, x y, y x),(y z, z x, x y)` Applying R 1 → R 1 R 2 R 3, we get LHS = `(2(x y z), 2(x y z),2(xStack Exchange network consists of 176 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack Exchange




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